udowodnij tożsamości sin⁴x+cos⁴x=1-2sin²x*coś²x
L=sin⁴x+cos⁴x=(sin²x+cos²x)²-2sin²xcos²x=1-2sin²xcos²x
P=1-sin²xcos²x
L=P
sin²x+cos²x=1
(a+b)²=a²+b²+2ab
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L=sin⁴x+cos⁴x=(sin²x+cos²x)²-2sin²xcos²x=1-2sin²xcos²x
P=1-sin²xcos²x
L=P
sin²x+cos²x=1
(a+b)²=a²+b²+2ab