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p₁ = 6²
p₁ = 36.
*po usunięciu 2 sześcianów pozostało 6 z nich, o wymiarach 3 na 3; a więc:
p = 2ab + 2bc + 2ca
p = 2(6*3) + 2(3*9) + 2(6*9)
p = 2*18 + 2*27 + 2*54
p = 36 + 54 + 108
p = 198.
pole jest równe 54.
v = ?
v = a³
v = 6 * (a³)
v = 6 * (3³)
v = 6 * 27
v = 162.