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x=3y-2
xy=133
sustituimos x=3y-2 en la segunda ecuacion
xy=133
(3y-2)y=133
3y²-2y=133
3y²-2y-133=0
(3y+19)(y-7)=0
3y+19=0 y-7=0
3y= -19 y=7
y= -19/3 y=7
tomamos el valor positivo
si =7
x=3y-2
x=3(7)-2
x=21-2
x=19
el numero mayor es el 19