Dane:
V = 340 [m/s]
f₁ = 16 [Hz]
f₂ = 20 [kHz] = 20000 [Hz]
[Hz] = [1/s]
Szukane:
λ₁ , λ₂
Rozw.:
λ = V × T
T = 1/f
wstawiamy drugi wzór do pierwszego i mamy
λ = V / f
czyli
λ₁ = V / f₁ = 340 [m/s] / 16 [1/s] = 21,25 m
λ₂ = V / f₂ = 340 [m/s] / 20000 [1/s] = 0,017 m = 17 mm
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Dane:
V = 340 [m/s]
f₁ = 16 [Hz]
f₂ = 20 [kHz] = 20000 [Hz]
[Hz] = [1/s]
Szukane:
λ₁ , λ₂
Rozw.:
λ = V × T
T = 1/f
wstawiamy drugi wzór do pierwszego i mamy
λ = V / f
czyli
λ₁ = V / f₁ = 340 [m/s] / 16 [1/s] = 21,25 m
λ₂ = V / f₂ = 340 [m/s] / 20000 [1/s] = 0,017 m = 17 mm