Rozwiąz równania:a)2x⁷+x⁶-3x⁵=0b)x³-3x²-5x+15=0
a)
2x⁷+x⁶-3x⁵ = 0
x⁵(2x²+x-3) = 0
x = 0
lub
2x²+x-3 = 0
Δ = b²-4ac = 1+24 = 25
√Δ = 5
x1 = (-b-√Δ)/2a = (-1-5)4 = -6/4 = -1,5
x2 = (-b+√Δ)/2a = (-1+5)/4 = 4/4 = 1
Odp. x = -1,5 v x = 0 v x = 1
b)
x³-3x²-5x+15 = 0
x²(x-3)-5(x-3) = 0
(x-3)(x²-5) = 0
(x-3)(x+√5)(x-√5) = 0
x = 3 v x = -√5 v x = √5
Odp. x = -√5 v x = √5 v x = 3
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a)
2x⁷+x⁶-3x⁵ = 0
x⁵(2x²+x-3) = 0
x = 0
lub
2x²+x-3 = 0
Δ = b²-4ac = 1+24 = 25
√Δ = 5
x1 = (-b-√Δ)/2a = (-1-5)4 = -6/4 = -1,5
x2 = (-b+√Δ)/2a = (-1+5)/4 = 4/4 = 1
Odp. x = -1,5 v x = 0 v x = 1
b)
x³-3x²-5x+15 = 0
x²(x-3)-5(x-3) = 0
(x-3)(x²-5) = 0
(x-3)(x+√5)(x-√5) = 0
x = 3 v x = -√5 v x = √5
Odp. x = -√5 v x = √5 v x = 3