Dany jest ciąg geometryczny określony wzorem
Oblicz iloraz ciągu oraz sumę sześciu początkowych jego wyrazów
a1 = -5(-2)1
a1 = -5 * -2 = 10
a2 = -5(-2)^2
a2 = -5 4 = -20
a3 = -5(-2)^3
a3= -5 * -8 = 40
obliczamy q
a3/a2 = 40/-20 = -2
a2/21 = -20/10 = -2
q = -2
a6 = -5 ( -2)^6
a6 = -5 * 64 = -320
Sn = ( 1 -q^n / 1 -q ) a1
S6 = ( 1 - 64 / 3 ) * 10
S6 = -63/3 *10 = - 210
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a1 = -5(-2)1
a1 = -5 * -2 = 10
a2 = -5(-2)^2
a2 = -5 4 = -20
a3 = -5(-2)^3
a3= -5 * -8 = 40
obliczamy q
a3/a2 = 40/-20 = -2
a2/21 = -20/10 = -2
q = -2
a6 = -5 ( -2)^6
a6 = -5 * 64 = -320
Sn = ( 1 -q^n / 1 -q ) a1
S6 = ( 1 - 64 / 3 ) * 10
S6 = -63/3 *10 = - 210