Oblicz pięc początkowych wyrazów ciągu określonego wzorem:
a_n=
a1=(-4)^1 * (1-1) = -4 * 0 = 0
a2=(-4)^2*(4-1) = 16 * 3 = 48
a3=(-4)^3 * (9-1) = -64 * 8= -512
a4=(-4)^4 * (16-1)= 256 * 15 = 3840
a5 = (-4)^5 * (25-1)=-1024*24=-24576
a₁=(-4)¹·(1²-1)= -4·0=0
a₂=(-4)²·(2²-1)=16·(4-1)=16·3=48
a₃=(-4)³·(3²-1)= -64(9-1)= -64·8= -512
a₄=(-4)⁴·(4²-1)= 256(16-1)= 256·15=3840
a₅=(-4)⁵·(5²-1)= -1024(25-1)= -1024·24= -24576
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a1=(-4)^1 * (1-1) = -4 * 0 = 0
a2=(-4)^2*(4-1) = 16 * 3 = 48
a3=(-4)^3 * (9-1) = -64 * 8= -512
a4=(-4)^4 * (16-1)= 256 * 15 = 3840
a5 = (-4)^5 * (25-1)=-1024*24=-24576
a₁=(-4)¹·(1²-1)= -4·0=0
a₂=(-4)²·(2²-1)=16·(4-1)=16·3=48
a₃=(-4)³·(3²-1)= -64(9-1)= -64·8= -512
a₄=(-4)⁴·(4²-1)= 256(16-1)= 256·15=3840
a₅=(-4)⁵·(5²-1)= -1024(25-1)= -1024·24= -24576