Rozwiazcie plizz Algebre.Dam naj :)
a)(2x-1)(2x+1)=9+4x(x+5)
b)(3z+2)(3z-2)=7z+9(z^{2}-2)
(2x-1)(2x+1)=9+4x(x+5)
4x²-1=9+4x²+20x
4x²-4x²-20x=9+1
-20x=10 /:(-20)
x=½
(3z+2)(3z-2)=7z+9(z^{2}-2)
9z²-4=7z+9z²-18
9z²-9z²-7z=-18+4
-7z=-14 /:(-7)
z=2
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(2x-1)(2x+1)=9+4x(x+5)
4x²-1=9+4x²+20x
4x²-4x²-20x=9+1
-20x=10 /:(-20)
x=½
(3z+2)(3z-2)=7z+9(z^{2}-2)
9z²-4=7z+9z²-18
9z²-9z²-7z=-18+4
-7z=-14 /:(-7)
z=2