Rozwiaz
2x^3- x^2- 6x + 3= 0
2x³-x²-6x+3=0
x²(2x-1)-3(2x-1)=0
(x²-3)(2x-1)=0
(x-√3)(x+√3)(2x-1)=0
x-√3=0 lub x+√3=0 lub 2x-1=0
x=√3 x=-√3 x=1/2
x^2(2x-1)-3(2x-1)=0
x^2-3=0 u 2x-1=0
x^2=3 2x=1
x=±√3 x=1/2
odp,
x=-√3 ∨ x=√3 ∨ x=1/2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2x³-x²-6x+3=0
x²(2x-1)-3(2x-1)=0
(x²-3)(2x-1)=0
(x-√3)(x+√3)(2x-1)=0
x-√3=0 lub x+√3=0 lub 2x-1=0
x=√3 x=-√3 x=1/2
x^2(2x-1)-3(2x-1)=0
x^2-3=0 u 2x-1=0
x^2=3 2x=1
x=±√3 x=1/2
odp,
x=-√3 ∨ x=√3 ∨ x=1/2