rozwiaz rownanie:
tg^2x(tgx-1)-3(tgx-1)= 0
(tgx-1)(tg^2x-3)=0
(tgx-1)(tgx- \/3)(tgx+\/3)=0
tgx=1 v tgx = \/3 v tgx=-\/3
x =π/4 +k π v x= π/3 + kπ v x = 2π/3 +kπ v x = 5π/3 +kπ
\/ - pierwiastek
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tg^2x(tgx-1)-3(tgx-1)= 0
(tgx-1)(tg^2x-3)=0
(tgx-1)(tgx- \/3)(tgx+\/3)=0
tgx=1 v tgx = \/3 v tgx=-\/3
x =π/4 +k π v x= π/3 + kπ v x = 2π/3 +kπ v x = 5π/3 +kπ
\/ - pierwiastek