rozwiaz rownanie:
Δ = (-3)² + 4*1*10 = 9+40 = 49
√Δ = 7
t₁ = 3-7/2 = -2
t₂ = 3+7/2 = 5
4t - 8 ≠ 0
t ≠ 2
t² - 4 ≠ 0
t≠ 2 , -2
D = R \ {-2,2}
T = 5
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Δ = (-3)² + 4*1*10 = 9+40 = 49
√Δ = 7
t₁ = 3-7/2 = -2
t₂ = 3+7/2 = 5
4t - 8 ≠ 0
t ≠ 2
t² - 4 ≠ 0
t≠ 2 , -2
D = R \ {-2,2}
T = 5