September 2018 1 21 Report

rozwiąż układy równań(w klamerkach):

a)

\frac{x+2y}{3} - \frac{2x+y}{3} = -3

\frac{3x-2y}{4} - \frac{3x+2y}{4} = \frac{3}{4}

b)

\frac{3x-2y}{6} + \frac{9x+y}{2} = - \frac{5}{3}

\frac{2x+3y}{2} - \frac{7x+4y}{3} = \frac{4}{9}

c)

\frac{x}{3} - 2 = y - 2

\frac{x+6}{3} + 3 (y -2) = 0


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