September 2018 1 12 Report

Rozwiąż układy równań:
( każde w klamerce)
a)
3(x+5)-4(y+3)=2(x+y)
2x-5(3+y)=4(2x+8)
b)
2(x+3)-3(x+y)=8
5x-3y=1
c)
(x+3)(x+4)-(y+8)(y+1)=x(x+5)-y(y-4)
x+3y=0
d)
4x(x+5)-8x(y+3)+4y^2=4(x-y)
2x+3(y+1)=2


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.