rozwiąż równanie
a) 2x(x - 1) = 1 + 2x kwadrat
b) 2x(x- 1) - xkwadrat = (1+x)x
^2 - druga potęga(kwadrat)
a) 2x(x - 1) = 1 + 2x^2
2x^2 - 2x = 1 + 2x^2
-2x = 1 + 2x^2 - 2x^2
-2x= 1 /: (-2)
x= - 1/2
b) 2x(x - 1) - x^2 = (1+x)x
2x^2 - 2x - x^2 = x + x^2
x^2 - 2x = x + x^2
x^2 - x^2 = x + 2x
0 = 3x
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^2 - druga potęga(kwadrat)
a) 2x(x - 1) = 1 + 2x^2
2x^2 - 2x = 1 + 2x^2
-2x = 1 + 2x^2 - 2x^2
-2x= 1 /: (-2)
x= - 1/2
b) 2x(x - 1) - x^2 = (1+x)x
2x^2 - 2x - x^2 = x + x^2
x^2 - 2x = x + x^2
x^2 - x^2 = x + 2x
0 = 3x