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sin²x+cos²x = 1
Rozwiązujemy równanie:
sin²x+2cosx = 2
1-cos²x+2cosx = 2
-cos²x+2cosx-1 = 0
cos²x-2cosx+1 = 0
(cosx-1)² = 0
cosx = 1
x = 2kπ, gdzie k∈C