Rozwiąż równania
b)1+√3x=x+2
√3x-x=2-1
x(√3-1)=1
x=1/(√3-1) =(√3+1)/(3-1) =(√3+1)/2
d)2x+3+x√3=4
2x+x√3=4-3
x(2+√3)=1
x=1/(2+√3)=(2-√3)/(4-3)= (2-√3)
f)√5(x-√5)=10-x
√5x-5=10-x
√5x+x=10+5
x(√5+1)=15
x=15/(√5+1)=(√5-1)/(5-1) =(√5-1)/4
h)(2x-3)/x√7=1/2
x√7 =2(2x-3)
x√7=4x-6
x√7-4x=-6
x(√7-4)=-6
x=-6/(√7-4)=6(√7+4)/(7-16) =(6√7+24)/-9
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b)1+√3x=x+2
√3x-x=2-1
x(√3-1)=1
x=1/(√3-1) =(√3+1)/(3-1) =(√3+1)/2
d)2x+3+x√3=4
2x+x√3=4-3
x(2+√3)=1
x=1/(2+√3)=(2-√3)/(4-3)= (2-√3)
f)√5(x-√5)=10-x
√5x-5=10-x
√5x+x=10+5
x(√5+1)=15
x=15/(√5+1)=(√5-1)/(5-1) =(√5-1)/4
h)(2x-3)/x√7=1/2
x√7 =2(2x-3)
x√7=4x-6
x√7-4x=-6
x(√7-4)=-6
x=-6/(√7-4)=6(√7+4)/(7-16) =(6√7+24)/-9