Rozwiąź nierówność:
4x^3 - 7x + 3 >0
t=x
4t²-7t+3>0
Δ=1 √Δ=1
t₁=1 t₂=¾
x=1 x=¾
x∈(-∞,¾)∨(1,∞)
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t=x
4t²-7t+3>0
Δ=1 √Δ=1
t₁=1 t₂=¾
x=1 x=¾
x∈(-∞,¾)∨(1,∞)