Rozłóz wielomiany na czynniki:
a).6x³+2x²+6x+2=
b).x³+5x²+6x=
6x³+2x²+6x+2=
2x²[3x+1]+2[3x+1]=
[2x²+2][3x+1]
x³+5x²+6x=
x[x²+5x+6]=
Δ=b²-4ac=5²-4×6=25-24=1
Δ=1
x₁=[-b-√Δ]/2a=[-5-1]/2=-3
x₂=[-b+Δ]/2a=[-5+1]/2=-2
x[x+3][x+2]
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6x³+2x²+6x+2=
2x²[3x+1]+2[3x+1]=
[2x²+2][3x+1]
x³+5x²+6x=
x[x²+5x+6]=
Δ=b²-4ac=5²-4×6=25-24=1
Δ=1
x₁=[-b-√Δ]/2a=[-5-1]/2=-3
x₂=[-b+Δ]/2a=[-5+1]/2=-2
x[x+3][x+2]