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a) a . b + 4 = 1 + 4 = 5
b) No pueden sumarse vectores con escalares, (b . c) es un escalar.
c) 2 (a . b) c - b = 2 . 1 . (0, -1, 0) - (0, 1, 1) = (0, -3. -1)
d) 3 (a + b) - 2 c = 3 [(1, 2, -1) + (0,1, 1)] - 2 (0, -1, 0) = (3, 11, 0)
Saludos Herminio