punkt s jest srodkiem odcinka AB. Oblicz a i b jeslu A(4,2), B(a,b), S(-2,3)
(4 + a) / 2 = - 2
4 + a = - 4
a = - 4 - 4
a = -8
(2 + b) / 2 = 3
2 + b = 6
b = 6 - 2
b = 4
A=(4;2)
B=(a;b)
S=(-2;3)
-2=(a+4)/2
a+4=-4
a=-8
3=(b+2)/2
b+2=6
b=4
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(4 + a) / 2 = - 2
4 + a = - 4
a = - 4 - 4
a = -8
(2 + b) / 2 = 3
2 + b = 6
b = 6 - 2
b = 4
A=(4;2)
B=(a;b)
S=(-2;3)
-2=(a+4)/2
a+4=-4
a=-8
3=(b+2)/2
b+2=6
b=4