Przedstaw podane wyrazenie za pomoca sumy algebraicznej
(3y-4)(5y+1)-(3y-4)+2(5y+1)+(y-2)(y+2)
Wzory skróconego mnożenia:
(a+b)²=a²+2ab+b² - kwadrat sumy;
(a-b)²=a²-2ab+b² - kwadrat różnicy;
a²-b²=(a-b)(a+b) - różnica kwadratów;
===================================
(3y-4)(5y+1)-(3y-4)²+2(5y+1)²+(y-2)(y+2)=
=15y²-20y+3y-4 - [9y²-24y+16] + 2[25y²+10y+1] + y²-4=
=15y²-17y-4 - 9y²+24y-16 + 50y²+20y+2 + y²-4=
=57y²+27y-22
(3y-4)(5y+1)-(3y-4)²+2(5y+1)²+(y-2)(y+2)=(15y²-20y+3y-4)-(9y²-24y+16)+2(25y²+10y+1)+y²-4 =
15y²-17y-4-9y²+24y-16+50y²+20y+2+y²-4 =57y²+27y-22
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Wzory skróconego mnożenia:
(a+b)²=a²+2ab+b² - kwadrat sumy;
(a-b)²=a²-2ab+b² - kwadrat różnicy;
a²-b²=(a-b)(a+b) - różnica kwadratów;
===================================
(3y-4)(5y+1)-(3y-4)²+2(5y+1)²+(y-2)(y+2)=
=15y²-20y+3y-4 - [9y²-24y+16] + 2[25y²+10y+1] + y²-4=
=15y²-17y-4 - 9y²+24y-16 + 50y²+20y+2 + y²-4=
=57y²+27y-22
(3y-4)(5y+1)-(3y-4)²+2(5y+1)²+(y-2)(y+2)=(15y²-20y+3y-4)-(9y²-24y+16)+2(25y²+10y+1)+y²-4 =
15y²-17y-4-9y²+24y-16+50y²+20y+2+y²-4 =57y²+27y-22