prosze o wykonanie obliczeń do tych zadań, a nie same odpowiedzi, to jest ze zbioru zadań "Matematyka w otaczającym nas świecie" klasa 1
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g)![5^{-13}\ :\ [5^{-18} \cdot (\frac{1}{5})^{-8}] = 5^{-13}\ :\ [5^{-18} \cdot 5^{8}] = 5^{-13}\ :\ 5^{-10} = 5^{-13-(-10)} = 5^{-3} = \frac{1}{125} 5^{-13}\ :\ [5^{-18} \cdot (\frac{1}{5})^{-8}] = 5^{-13}\ :\ [5^{-18} \cdot 5^{8}] = 5^{-13}\ :\ 5^{-10} = 5^{-13-(-10)} = 5^{-3} = \frac{1}{125}](https://tex.z-dn.net/?f=5%5E%7B-13%7D%5C+%3A%5C+%5B5%5E%7B-18%7D+%5Ccdot+%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-8%7D%5D+%3D+5%5E%7B-13%7D%5C+%3A%5C+%5B5%5E%7B-18%7D+%5Ccdot+5%5E%7B8%7D%5D+%3D+5%5E%7B-13%7D%5C+%3A%5C+5%5E%7B-10%7D+%3D+5%5E%7B-13-%28-10%29%7D+%3D+5%5E%7B-3%7D+%3D+%5Cfrac%7B1%7D%7B125%7D)
h)
i)![3^{-11} \cdot [(\frac{1}{3})^{15}\ :\ 3^{-24}] = 3^{-11} \cdot [3^{-15}\ :\ 3^{-24}] = 3^{-11} \cdot [3^{-15-(-24)}] = 3^{-11} \cdot 3^{9}=\\=3^{-11+9} = 3^{-2} = \frac{1}{9} 3^{-11} \cdot [(\frac{1}{3})^{15}\ :\ 3^{-24}] = 3^{-11} \cdot [3^{-15}\ :\ 3^{-24}] = 3^{-11} \cdot [3^{-15-(-24)}] = 3^{-11} \cdot 3^{9}=\\=3^{-11+9} = 3^{-2} = \frac{1}{9}](https://tex.z-dn.net/?f=3%5E%7B-11%7D+%5Ccdot+%5B%28%5Cfrac%7B1%7D%7B3%7D%29%5E%7B15%7D%5C+%3A%5C+3%5E%7B-24%7D%5D+%3D+3%5E%7B-11%7D+%5Ccdot+%5B3%5E%7B-15%7D%5C+%3A%5C+3%5E%7B-24%7D%5D+%3D+3%5E%7B-11%7D+%5Ccdot+%5B3%5E%7B-15-%28-24%29%7D%5D+%3D+3%5E%7B-11%7D+%5Ccdot+3%5E%7B9%7D%3D%5C%5C%3D3%5E%7B-11%2B9%7D+%3D+3%5E%7B-2%7D+%3D+%5Cfrac%7B1%7D%7B9%7D)