Prosze o pomoc ! Oblicz miejsca zerowe ciągow :
an = log(n-7) bn= n3 - 5n2 - 4n +20
an = log (n - 7)
n∈N ∧ n ≥ 1
0 = log (n - 7)
log 1 = log (n - 7)
1 = n - 7
n = 8
bn= n³ - 5n² - 4n + 20
0 = n³ - 5n² - 4n + 20
0 = n²(n-5) - 4(n-5)
0 = (n² - 4)(n-5)
0 = (n-2)(n+2)(n-5)
n - 2 = 0 v n + 2 = 0 v n - 5 = 0
n = 2 v n = -2 ∉ N v n = 5
n = 2 v n = 5
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an = log (n - 7)
n∈N ∧ n ≥ 1
0 = log (n - 7)
log 1 = log (n - 7)
1 = n - 7
n = 8
bn= n³ - 5n² - 4n + 20
n∈N ∧ n ≥ 1
0 = n³ - 5n² - 4n + 20
0 = n²(n-5) - 4(n-5)
0 = (n² - 4)(n-5)
0 = (n-2)(n+2)(n-5)
n - 2 = 0 v n + 2 = 0 v n - 5 = 0
n = 2 v n = -2 ∉ N v n = 5
n = 2 v n = 5