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sinα = AB/A₁B
AB = 3
A₁B = 9
sinα = 3/9
sinα = 1/3
b)
sinα = AC/A₁C
AC = D₁B₁ = 4√2
A₁C = 8
sinα = 4√2/8 = √2/2
c)
cosα = AB/A₁B
AB to bok trójkąta równobocznego, którego wysokość równa się 4√3
AB√3/2 = 4√3 /×2
AB√3 = 8√3 / ÷√3
AB = 8
A₁B = 16
cosα = 8/16
cosα = 1/2