Proszę o rozwiązanie podanych przykładów.:) Z góry dziękuję.
3^(log3 5) + log5 25^3 = 5 + log5 (5^2)^3 = 5 + log5 5^6 = 5 + 6log5 5 = 5 + 6 = 11
27^log3 2 - log27 1 = (3^3)^log3 2 - log27 27^0 = 3^(3log3 2) - 0 * log27 27 =
3^log3 2^3 - 0 * 1 = 3^log3 8 - 0 = 8 - 0 = 8
64^log2 √3 + log√3 (√3)^3 = (2^6)^log2 √3 + 3 * log√3 √3 = 2^(6 * log2 √3) + 3 * 1 =
2^log2 (√3)^6 + 3 = (√3)^6 + 3 = [ (√3)² ]³ + 3 = 3³ + 3 = 27 + 3 = 30
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3^(log3 5) + log5 25^3 = 5 + log5 (5^2)^3 = 5 + log5 5^6 = 5 + 6log5 5 = 5 + 6 = 11
27^log3 2 - log27 1 = (3^3)^log3 2 - log27 27^0 = 3^(3log3 2) - 0 * log27 27 =
3^log3 2^3 - 0 * 1 = 3^log3 8 - 0 = 8 - 0 = 8
64^log2 √3 + log√3 (√3)^3 = (2^6)^log2 √3 + 3 * log√3 √3 = 2^(6 * log2 √3) + 3 * 1 =
2^log2 (√3)^6 + 3 = (√3)^6 + 3 = [ (√3)² ]³ + 3 = 3³ + 3 = 27 + 3 = 30