Proszę o rozwiazanie jednego krótkiego przykładu , daje NAJ , zadanie w załączniku
D: x ≠ 4
2 - 5x = 8 / (x - 4) /*(x - 4)
(2 - 5x) * (x - 4) = 8
2x - 8 - 5x² + 20x - 8 = 0
-5x² + 22x - 16 = 0
Δ = 22² - 4 * (-5) * (-16) = 484 - 320 = 164
√Δ = √164 = 2√41
x1 = (-22 - 2√41)/(-10) = (11 - √41) / 5
x1 = (-22 + 2√41)/(-10) = (11 - √41) / 5
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D: x ≠ 4
2 - 5x = 8 / (x - 4) /*(x - 4)
(2 - 5x) * (x - 4) = 8
2x - 8 - 5x² + 20x - 8 = 0
-5x² + 22x - 16 = 0
Δ = 22² - 4 * (-5) * (-16) = 484 - 320 = 164
√Δ = √164 = 2√41
x1 = (-22 - 2√41)/(-10) = (11 - √41) / 5
x1 = (-22 + 2√41)/(-10) = (11 - √41) / 5