Proszę o pomoc w rozwiązaniu logarytmów.
Zadanie w załączniku. Z góry dziękuję.
a)
log125=3log5
log125=log5³
log125=log125
b)
log₅12=2log₅2+log₅3
log₅12=log₅4+log₅3
log₅12=log₅(4*3)
log₅12=log₅12
c)
log₇12-log₇2=log₇6
log₇(12:2)=log₇6
log₇6=log₇6
d)
5log₉2+2log₉1/4=log₉2
log₉32+log₉1/16=log₉2
log₉(32*1/16)=log₉2
log₉2=log₉2
e)
3log3+2log2-log6=log18
log27+log4-log6=log18
log(27*4:6)=log18
log18=log18
f)
log₃2=-7log₃1/2-3log₃4
log₃2=log₃128-log₃64
log₃2=log₃(128:64)
log₃2=log₃2
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a)
log125=3log5
log125=log5³
log125=log125
b)
log₅12=2log₅2+log₅3
log₅12=log₅4+log₅3
log₅12=log₅(4*3)
log₅12=log₅12
c)
log₇12-log₇2=log₇6
log₇(12:2)=log₇6
log₇6=log₇6
d)
5log₉2+2log₉1/4=log₉2
log₉32+log₉1/16=log₉2
log₉(32*1/16)=log₉2
log₉2=log₉2
e)
3log3+2log2-log6=log18
log27+log4-log6=log18
log(27*4:6)=log18
log18=log18
f)
log₃2=-7log₃1/2-3log₃4
log₃2=log₃128-log₃64
log₃2=log₃(128:64)
log₃2=log₃2