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a²+b²=c²
3²+(1/√2)²=c²
9+1/2=c²
c=√(9 i1/2)
a = 3dm
b= 1/√2
d=?
to zadanko można obliczyć za pomocą twierdzenia Pitagorasa :)
d² = a² + b²
d²= 3² + (1/ √2)²
d²= 9 + 1/2
d²= 9 1/2 / √
d= √19/2 dm