Pilne, na teraz!!!!
Ile gramów kwasu azotowego(V) potrzeba aby przeprowadzić nitrowanie 156gram benzenu?
mC6H6=78u
mHNO3=63u
C6H6 + HNO3 --H2SO4--> C6H5NO2 + H2O
78g benzenu ----- 63g kwasu
156g benzenu ------ xg kwasu
x = 126gkwasu
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mC6H6=78u
mHNO3=63u
C6H6 + HNO3 --H2SO4--> C6H5NO2 + H2O
78g benzenu ----- 63g kwasu
156g benzenu ------ xg kwasu
x = 126gkwasu