Question

Persamaan kuadrat yang akar2nya satu lebih besar dari akar2 persamaan 2x^-x-5=0 adalah...

Answer 1

2x² - x - 5 = 0
a=2; b=-1; c=-5
akar2nya = x1 dan x2

=> x1 + x2 = -b/a = 1/2

=> x1 X x2 = c/a = -5/2

akar2 persamaan kuadrat baru = x1+1 dan x2+1

=> (x1+1) + (x2+1)
= x1 + x2 + 2
= 1/2 + 2 = 5/2

=> (x1+1) (x2+1)
= x1 . x2 + 1(x1+x2) + 1
= -5/2 + 1(1/2) + 1
= -5/2 + 1/2 + 1 = -1

Persamaan kuadrat baru = x² - ((x1+1) + (x2+1))x + ((x1+1) (x2+1)) = 0
=> x² -5/2x - 1 = 0
=> 2x² - 5x - 2 = 0

Semoga bermanfaat ^_^