oblicz:
odp: 2
√(3 + 2√2) - √(3 - 2√2) = n
(√(3 + 2√2) - √(3 - 2√2))² = n²
(3 + 2√2) - 2(√(3 + 2√2)(3 - 2√2)) + (3 - 2√2) = n²
6 - 2(√(9 - 8)) = n²
6 - 2 = n²
4 = n²
2 = n
1-√2<0, stad I1-√2I=√2-1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
√(3 + 2√2) - √(3 - 2√2) = n
(√(3 + 2√2) - √(3 - 2√2))² = n²
(3 + 2√2) - 2(√(3 + 2√2)(3 - 2√2)) + (3 - 2√2) = n²
6 - 2(√(9 - 8)) = n²
6 - 2 = n²
4 = n²
2 = n
1-√2<0, stad I1-√2I=√2-1