Oblicz.
a)log4 - log5 + log125
b)log4-log4000
c)log0,03-log3
d)
e)
f)log100000
Prosze o obliczenia :)
a)log4-log5+log125=log((4/5)*125)=log100=2
b)log4-log4000=log(1/1000)=log1000^{-1}=-3
c)log0,03-log3=log0,01=-2
zatem:
x=3/2
f)log100000=log10^{5}=5
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a)log4-log5+log125=log((4/5)*125)=log100=2
b)log4-log4000=log(1/1000)=log1000^{-1}=-3
c)log0,03-log3=log0,01=-2
d)
zatem:
e)
x=3/2
f)log100000=log10^{5}=5