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h=a√3:2=8√3;2=4√3cm
z pitagorasa obliczam H bryły
H²=12²-(4√3)²
H²=144-48
H=4√6cm= wysokość bryły
pole podstawy=a²√3:4=8²√3:4=16√3cm²
v=⅓×16√3×4√6=64√2cm³