Oblicz skład procentowy związku Mg(OH)₂
mMg(OH)₂=24u+2*16u+2*1u=24u+32u+2u=58u
mMg=24u
58u - 100%
24u - x%
x=(24u*100%):58u≈41,4% magnezu
mO=2*16u=32u
32u - x%
x=(32u*100%):58u≈55,2% tlenu
mH=2*1u=2u
2u - x%
x=(2u*100%):58u≈3,4% wodoru
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mMg(OH)₂=24u+2*16u+2*1u=24u+32u+2u=58u
mMg=24u
58u - 100%
24u - x%
x=(24u*100%):58u≈41,4% magnezu
mO=2*16u=32u
58u - 100%
32u - x%
x=(32u*100%):58u≈55,2% tlenu
mH=2*1u=2u
58u - 100%
2u - x%
x=(2u*100%):58u≈3,4% wodoru