Question

Oblicz:

sin(2x-1)=1
cos3x=-0,5
sing3x=sin4x

Answer 1

A)
2x-1=π/2+2kπ
2x=1+π/2+2kπ
x=1/2+π/4+kπ, k∈C
b)
3x=2/3)π+2kπ   lub   3x=4/3)π+2kπ
x=(2/9)π+(2/3)kπ   lub   x=(4/9)π+(2/3)π,  k∈C
c)
sin4x-sin3x=0
2sin(x/2)cos(7x/2)=0
sin(x/2)=0  ∨  cos(7x/2)=0
x/2=kπ   ∨ 7x/2=π/2+kπ
x=2kπ  ∨  x=π/7 +(2kπ)/7,  k∈C