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1+3x^3-x^6=t różniczkujemy
9x^2-6x^5)dx=dt
-3(2x^5-3x^2)dx=dt
(2x^5-3x^2)dx=dt/(-3)
obliczamy całkę
(-1/3)∫dt/t=(-1/3)lnItI+C=(-1/3)lnI1+3x^3-x^6I +C