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v'=x²⇒ v=1/3·x³
J=1/3x²·ln(x+1)- 1/3calka x³/(1+x²)
x³/(1+x²)=(x³+x-x)/(1+x²)=[x(1+x²)-x]/(1+x²)=x-x/(1+x²)
calka(-x/(1+x²)=-1/2ln(1+x²) chyba czytam w Twoich myslach