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sinα = 1/3 /()²
sin²α = 1/9
sin²α + cos²α = 1
1/9 + cos²α = 1
cos²α = 1- 1/9
cos²α = 8/9 /√
cosα = √8/3
cosα = √4*√2 / 3
cosα = 2√2 / 3
(sinα + cosα)² = sin²α + 2sinαcosα + cos²α = 1 + 2sinαcosα
1 + 2sinαcosα = 1 + 2*1/3 * 2√2/3 = 1 + 2/3*2√2/3 = 1 + 4√2/9 =1 + 4/9*√2
Rozwiązanie w załączniku.