zad.3 l - średnica a) O = 2πr = πl = π * 6,28 cm = 19,7192cm b) O = 2πr = πl = π * 12,56dm = 39,4384dm c) O = 2πr = πl = π * 31,40 = 98,596dm d) O = 2πr = πl = π * 47,1cm = 147,894cm
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miceklol
Zad1 a)wzór na obwód koła O=2πr 12π=2πr /:π 12=2r /:2 r=6(cm) b)1.4π=2πr /:π 1.4=2r /:2 r=0.7(cm) c)6π=2πr /:π 6=2r /:2 r=3(cm) Zad2 średnica = ś ś=2r r=2.5(cm) O=2 x 3.14 x 2.5 =15.7(cm) Zad3 a) ś=2r r=3.14 2 x 3.14 x 3.14=19.7192(cm) b)r=62.8(cm) 2 x 3.14 x 62.8 =394.384 c)r=157(cm) 2 x 157 x 3.14 =985.96 d)r=23.55(cm) 2 x 23.55 x 3.14=147.894(cm)
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maddelaine
Obw=2IIr r=ob/2II a) r= 12II/2II=6 d=12 b) r=1,4II/2II=0,7 d=1,4 c)r=6II/2II=3 d=6
zad.3 r=1/2d obw=2II*1/2d a) obw= 2II*1/2*6,28= 2*3,14*3,14=19,7192cm b) obw=2II* 1/2*12,56=2*3,14*6,28=39,4384dm c) obw= 2II*1/2*31,4=2*3,14*15,7=98,596dm d) obw=2II*1/2*47,1=2*3,14*23,55=147,894cm
zad. 1
a) 12π = 2πr
r = 6, średnica = 12
b)
a) 1,4π = 2πr
r = 0,7, średnica = 1,4
c) 6π = 2πr
r = 3, srednica = 6
zad.2
O = 2πr = 5π cm = 15,7 cm
zad.3
l - średnica
a) O = 2πr = πl = π * 6,28 cm = 19,7192cm
b) O = 2πr = πl = π * 12,56dm = 39,4384dm
c) O = 2πr = πl = π * 31,40 = 98,596dm
d) O = 2πr = πl = π * 47,1cm = 147,894cm
a)wzór na obwód koła O=2πr
12π=2πr /:π
12=2r /:2
r=6(cm)
b)1.4π=2πr /:π
1.4=2r /:2
r=0.7(cm)
c)6π=2πr /:π
6=2r /:2
r=3(cm)
Zad2
średnica = ś
ś=2r
r=2.5(cm)
O=2 x 3.14 x 2.5 =15.7(cm)
Zad3
a) ś=2r
r=3.14
2 x 3.14 x 3.14=19.7192(cm)
b)r=62.8(cm)
2 x 3.14 x 62.8 =394.384
c)r=157(cm)
2 x 157 x 3.14 =985.96
d)r=23.55(cm)
2 x 23.55 x 3.14=147.894(cm)
r=ob/2II
a) r= 12II/2II=6
d=12
b) r=1,4II/2II=0,7
d=1,4
c)r=6II/2II=3
d=6
zad.2
r=5cm/2=2,5cm
obw=2IIr
obw= 2 * 3,14 * 2,5 = 15,7cm
Obwód wynosi 15,7cm.
zad.3
r=1/2d
obw=2II*1/2d
a) obw= 2II*1/2*6,28= 2*3,14*3,14=19,7192cm
b) obw=2II* 1/2*12,56=2*3,14*6,28=39,4384dm
c) obw= 2II*1/2*31,4=2*3,14*15,7=98,596dm
d) obw=2II*1/2*47,1=2*3,14*23,55=147,894cm