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α = 168⁰
Pw - pole wycinka kołowego
P - pole koła
Pw : P = 168⁰ : 360⁰ = 7 / 15
Pw= (7/15)* P = (7/15* π r² = (7/15)*π* (30 cm)² =
= (7/15) *π * 900 cm² = 420 π cm².
Odp.Pole wycinka tego wycinka kołowego jest równe 420 π cm².