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Ob = 2πr
a) średnica = 6 cm
r = 6 : 2 = 3 cm
P = π3² = π9 cm²
Ob = 2 * 3π = 6π
b) r = 5 cm
P = π5² = π25 cm²
Ob = 2 * 5π = 10π
a nie umiem
ale b)
=
a obwod