oblicz obwód trójkąta ABC wiedząc,że A=(-2;-1),B=(7;2),C=(3;4)
P=1/2 I(XB-XA)(YC-YA)-(YB-YA)(XC-XA) I
P=1/2 I (2+2)(4-3)-(2+2)(3+2) I
P=1/2 I 4*1 - 4*5 I
P= 1/2 I 4-20I
P=1/2 I-16I
P=8
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P=1/2 I(XB-XA)(YC-YA)-(YB-YA)(XC-XA) I
P=1/2 I (2+2)(4-3)-(2+2)(3+2) I
P=1/2 I 4*1 - 4*5 I
P= 1/2 I 4-20I
P=1/2 I-16I
P=8