Oblicz następujące logarytmy:
log₄256 = log₄4⁴ = 4
log₃1/27 = log₃1/3³ = log₃3⁻³ = -3
log₃27 = log₃3³ = 3
log1/100 = log1/10² = log10⁻² = -2
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
a)
log4(256) = log4(16*16) = log4(4*4*4*4) = 4
b)
log3(1/27)=log3(1/3 * 1/3 * 1/3) = -3
c)
log3(27)=log3(3 * 3 * 3) = 3
d)
// log(x) = log10(x)
log10(1/100)=log10(1/10 * 1/10) = -2
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log₄256 = log₄4⁴ = 4
log₃1/27 = log₃1/3³ = log₃3⁻³ = -3
log₃27 = log₃3³ = 3
log1/100 = log1/10² = log10⁻² = -2
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
a)
log4(256) = log4(16*16) = log4(4*4*4*4) = 4
b)
log3(1/27)=log3(1/3 * 1/3 * 1/3) = -3
c)
log3(27)=log3(3 * 3 * 3) = 3
d)
// log(x) = log10(x)
log10(1/100)=log10(1/10 * 1/10) = -2