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11x*12=396
132x=396 |/132
x=3[dm]
Pierwsza podstawa- 3dm*5=15dm
Druga podstawa-3dm*6=18dm
druga podstawa 6x
pole trapezu (a+b)×h/2
(5x+6x)×24/2=396
11x×12=396
11x=396÷12
11x=33
x=3
pierwsza podstawa 5×3=15dm
druga podstawa 6×3=18dm