1. h=50 cm=0,5 m; T= 27+273=300 C; R=8,314 J/molK
V=Sh
pSh=nRT
F=pS
siła parcia
F=nRT/h= 4*8,314*300/0,5=19 953,6 N
F=20 kN
2. V=1,5 l=1,5*10^-3 m^3; m=20 g; M=2g/mol; p=1200 hPa=
=1200*100 Pa=1,2*10^5 Pa
ilość moli
n=m/M= 20/2=10 moli
temperatura gazu
T=pV/nR
Energia kinetyczna
Ek=3kT/2; k=1,38*10^-23 J/K
Ek= 3kpV/2nR Ek= 3*1,38*10^-23*1,2*10^5*1,5*10^-3/2*10*8,314 3*1,38*1,2*1,5/2*10*8,314=0,0448
10^(-23+5-3)=10^-21
Ek=4,48*10^-23 J
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1. h=50 cm=0,5 m; T= 27+273=300 C; R=8,314 J/molK
V=Sh
pSh=nRT
F=pS
siła parcia
F=nRT/h= 4*8,314*300/0,5=19 953,6 N
F=20 kN
2. V=1,5 l=1,5*10^-3 m^3; m=20 g; M=2g/mol; p=1200 hPa=
=1200*100 Pa=1,2*10^5 Pa
ilość moli
n=m/M= 20/2=10 moli
temperatura gazu
T=pV/nR
Energia kinetyczna
Ek=3kT/2; k=1,38*10^-23 J/K
Ek= 3kpV/2nR Ek= 3*1,38*10^-23*1,2*10^5*1,5*10^-3/2*10*8,314 3*1,38*1,2*1,5/2*10*8,314=0,0448
10^(-23+5-3)=10^-21
Ek=4,48*10^-23 J