Ile ml 96% H2SO4 o d=1,84g/ml i ile wody potrzeba do sporzadzenia 47,5g 15% r-ru tego kwasu o d=1,103g/ml?
Niby bnalne, ale czy miało wyjśc 4ml kwasu i 40,4 wody?
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ms= Cp * mr-ru = 7,13g
100g H2SO4 ---- 96g
xg ----------- 7,13g
x= 7,43g
d= m/v
v= m/d v= 7,43/ 1,84 = 4,04 ml
47,5g r-ru - 7,43g s = 40,07g H₂O