Liczby x-2,3,x+6 sa w podanej kolejnosci pierwszym,drugim,trzecim wyrazem ciagu artmetycznego.Oblicz x
x-2, 3, x+6
a1 a2 a3
a2 - a1 = a3 - a2
3 - (x - 2) = (x + 6) - 3
3 - x + 2 = x + 6 - 3
5 - x = x + 3
-x - x = 3 - 5
-2x = -2
x = -2 : (-2)
x = 1
a1=x-2
a2=3
a3=x+6
a2=a1+a3 /2
3=x-2+x+6 /2
3=2x+4 /2
6=2x+4
2x=2 /:2
x=1
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x-2, 3, x+6
a1 a2 a3
a2 - a1 = a3 - a2
3 - (x - 2) = (x + 6) - 3
3 - x + 2 = x + 6 - 3
5 - x = x + 3
-x - x = 3 - 5
-2x = -2
x = -2 : (-2)
x = 1
a1=x-2
a2=3
a3=x+6
a2=a1+a3 /2
3=x-2+x+6 /2
3=2x+4 /2
6=2x+4
2x=2 /:2
x=1