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pole = a²
koło obwód 2πr
pole πr²
4a = 2πr
a²/πr²=?
a=½πr
[½πr]/πr²=1/2r
obwód koła: 2πr
Stosunek pól: a²/πr²
4a = 2πr
a=½πr
[½πr]²/πr² = ¼π²r²/πr² = ¼π
Stosunek wynosi ¼π(kwadrat) : 1(koło)