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d = k / k-1 /* k-1
k = d * (k-1)
b)
e = k+1 / k+1 /* k+1
k+1 = e * (k+1) /-1
k = e * (k+1) - 1
c)
f = k+1 / k+a /*k+a
k+1 = f * (k+a) /-1
k = f * (k+a) -1
d)
g = 2-1 / k
k = 2-1 / g
a)
d = k/ k-1 |*(k-1)
k≠1
d(k-1) = k
dk - d = k
dk - k = d
k(d -1) = d |:(d - 1)
k = d / d-1
b)
e = k+1 / k+1
przy takim zapisie licznik i mianownik skraca się i wychodzi e = 1 i nie ma we wzorze k
c)
f = k+1/k + a |*k
k≠0
fk = k + 1 +ka
fk + k + ka = 1
k(a+f+1) = 1
k=1:(a+f+1)
d) g = 2 - 1/k |*k
k≠0
gk= 2k - 1
gk - 2k = -1
k(g-2) = -1
k= -1:(g-2)