January 2019 1 73 Report
Jika titik P (-2,3), Q (5,1) dan R tengah-tengah PQ. persamaan garis yang melalui R tegak lurus PQ adalah..
A. y+2x=1
B. 2x-y=-3
C. 2x+y=1
D. x-2y=-3
E. 3x+2y=-1
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